On the order modulo p of an algebraic number (for p large enough)
Résumé
Let $K/\Q$ be Galois of degree $n$, of Galois group $G$,
and let $\eta\in K^\times$ be given such that $\langle \eta \rangle_G \otimes \Q \simeq \Q[G]$.
For $p$ unramified in $K/\Q$ and prime to $\eta$, denote by $n_p$ the residue degree of $p$,
by $g_p$ the number of prime ideals ${\mathfrak p} \mid p$ then by
$o_{\mathfrak p}(\eta)$ and $o_p(\eta)$ the orders of $\eta$ modulo ${\mathfrak p}$ and $p$,
respectively.
In a first part, using Frobenius automorphisms, we show that for all $p$ large enough,
some explicit divisors of $p^{n_p}-1$ cannot realize $o_{\mathfrak p}(\eta)$ (Thms. 2.1, 4.1).
In a second part, we obtain that for all $p$ large enough such that $n_p > 1$ we have
${\rm Prob}(o_p(\eta) < p) \leq \frac{1}{p^{g_p\,(n_p-1) - \varepsilon}}$,
where $\varepsilon = O \big( \frac{1}{{\rm log}_2(p)}\big)$ (Thm. 6.1).
Thus, under the heuristic of Borel--Cantelli this yields $o_p(\eta) > p$ for all $p$ large enough such that $g_p(n_p-1) \geq 2$,
which covers the particular cases of cubic fields with $n_p=3$ and quartic fields with $n_p=2$, but not the quadratic fields with
$n_p=2$; in this case, the natural conjecture is, on the contrary, that $o_p(\eta) < p$ for infinitely many inert $p$ (Conj. 8.1).
Origine : Fichiers produits par l'(les) auteur(s)