On the spanning trees of the hypercube and other products of graphs
Résumé
We give two combinatorial proofs of a product formula for the number of spanning trees of the $n$-dimensional hypercube. The first proof is based on the assertion that if one chooses a uniformly random rooted spanning tree of the hypercube and orient each edge from parent to child, then the parallel edges of the hypercube get orientations which are independent of one another. This independence property actually holds in a more general context and has intriguing consequences. The second proof uses some ''killing involutions'' in oder to identify the factors in the product formula. It leads to an enumerative formula for the spanning trees of the $n$-dimensional hypercube augmented with diagonals edges, counted according to the number of edges of each type. We also prove more general counting formulas for the spanning trees of Cartesian products of complete graphs using a matrix-tree approach.
Domaines
Combinatoire [math.CO]
Origine : Fichiers produits par l'(les) auteur(s)