, Since H and J are continuous functions we also have H(u k+1 ) ? H(u) and J(u k ) ? J(u). Then, using Proposition A.2, we see that we can pass to the
, This means that for all v, we have: H(v) ? H(u k ) ? q k, We have q k ? ?H(u k )
,
The sequence u k in Algorithm 2 ,
, Proposition 5.1 and relation (1.13), we know that there exists 0 < ? J < +?
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