, Precomputation, independent of n 0
, decreasing order: a. Compute f
, > sup fF [ (n)] (p / q; k) : k > n + 1; k 2 / Z g (cf. (37)) using Algorithm 22, and set b = max (b 1 Otherwise
, If b is larger than the maximum of the S(k) dened so far, set S(n) = b
, Find the smallest n > n 0 on which S is dened
, There is no harm in also replacing () by zero in (30) when we take (n) = 1 because the origin is an ordinary point: doing so only makes the rst few terms of the bound innite
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